Question

$F=\frac{9}{5}C+32$.

Make C as the subject of formula

• A. $\frac{9}{5}(C-32)$
• B. $F\frac{5}{9}C+32$
• C. $\frac{9}{5}(F+32)$
• D. $\frac{5}{9}(F-32)$

Answer 1

The correct option is D $\frac{5}{9}(F-32)$

Given:

$F=\frac{9}{5}C+32$

Now arrenging,

$\Rightarrow 5F=9C+160$ [dividing by 5 both the side]

$\Rightarrow 9C=5F-160$

$\Rightarrow C=\frac{5F}{9}-\frac{160}{9}$

$\Rightarrow C=\frac{5}{9}(F-32)$ [taking 5/9 common]

Hence, formula for $C$ is $\frac{5}{9}(F-32)$.