Question 85 (f)
Evaluate 154×18333×52×122
We have 154×18333×52×122=(3×5)4×(2×32)333×52×(22×3)2=34×54×23×3633×52×24×32=34+6−3−2×54−224−3=35×522=243×252=60752
Question 85 (c)
Evaluate 125×52×a7103×a4
Question 85 (d)
Evaluate 34×123×3625×63
Evaluate: 52 – 92 + 33 × 42 ÷ 24
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Question 85 (g)
Evaluate 64×92×25332×42×156