F from R into R is defined as f x - - 2x - 5- if x - 0- 3x - 2- if x - 0 - Show that F is one -one-

Solution f( x ) = {[ 2x + 5, if x gt; 0; 3x 2, if x ≤ 0 ]. #160; #160; R→ R Range if x gt; 0 [5,∞ ] Range if x ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

One - One function

f from R in...

Question

$f$ from $R$ into $R$ is defined as
$f (x) = {\begin{matrix} 2 x + 5, i f x > 0 3 x - 2, i f x \leq 0 \end{matrix}$ Show that $F$ is one -one.

Open in App

Solution

Suggest Corrections

Similar questions

f : R \to R

f (x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{x + 2}{x^{2} + 3 x + 2}, & i f & x \in R - {- 1, - 2} - 1, & i f & x = - 2 0, & i f & x = - 1 \end{matrix}

f

Show that the Signum function $f : R \to R$ , given by

f (x) = ⎧ ⎨ ⎩ \begin{matrix} 1, i f x > 0 0, i f x = 0 - 1, i f x < 0 \end{matrix}

f : R \to R

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} 5, & i f & x \leq 1 a + b x, & i f & 1 < x < 3 b + 5 x, & i f & 3 \leq x < 5 30, & i f & x \geq 5 \end{matrix}

f

0 < a < 1

f

f (x) = {\begin{matrix} x^{a}; i f x > 0 0; i f x = 0 \end{matrix}

f : R \to R

f (x) = {1, if x > 00, if x = 0}

- 1

x < 0

Join BYJU'S Learning Program