F x -1x - x2 - 1x2Then fx can be

The correct option is B x^2 2 We will try to represent f(x+1x) in the form of x+1x and substitute x in the place x+1x .Given ...

296

You visited us 296 times! Enjoying our articles? Unlock Full Access!

Idea of a Set

f x +1x = x2...

Question

$f (x + \frac{1}{x}) = x^{2} + \frac{1}{x^{2}}$
Then $f (x)$ can be

2 - x^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} - 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{2} + 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 x^{2} - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = (\sqrt{x^{2} + 1} + \sqrt{x^{2} - 1})^{6} + {(\frac{2}{\sqrt{x^{2} + 1} + \sqrt{x^{2} - 1}})}^{6}

f (x) = {tan}^{- 1} (\frac{1 - \sqrt{x^{2} - 1}}{\sqrt{x^{2} + 2 \sqrt{x^{2} - 1}}}) + {sin}^{- 1} (\frac{\sqrt{x^{2} - 1}}{| x |})

tan (f (x)) = | x^{2} - 2 |

f (x) = {cos}^{- 1} (\frac{2 x}{1 + x^{2}})

f (x)

f (x) = {cos}^{- 1} (\frac{2 x}{1 + x^{2}})

f^{'} (x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \begin{matrix} \frac{- 2}{1 + x^{2}}, & | x | < 1 \end{matrix} \begin{matrix} \frac{2}{1 + x^{2}}, & | x | > 1 \end{matrix} \end{matrix}

f

f (x) = ⎧ ⎨ ⎩ \begin{matrix} \begin{matrix} \frac{x^{2} - 1}{x^{2} - 2 | x - 1 | - 1}, & x \neq 1 \end{matrix} \begin{matrix} \frac{1}{2}, & x = 1 \end{matrix} \end{matrix}

f (x) = \frac{x^{2} - 2}{\sqrt{1 + x^{2}}}

Join BYJU'S Learning Program