We have, #10; #10; f( x )=12sin^2x 1 #10; #10; =1 cos 2x #10; #10; = sec 2x #10; #10;Hence, this is the #10;answer. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Basic Inverse Trigonometric Functions

f x = 1 2sin ...

Question

$f (x) = \frac{1}{2 s i n^{2} x - 1}$

Open in App

Solution

We have,

$f (x) = \frac{1}{2 {sin}^{2} x - 1}$

$= \frac{1}{- c o s 2 x}$

$= - s e c 2 x$
Hence, this is the answer.

Suggest Corrections

Similar questions

f^{'} (x) = \frac{1 - 2 {sin}^{2} x}{f (x)}

f (x) > 0, \forall x \in R

f (0) = 1

f (x)

f (x) = \frac{2 {sin}^{2} x + 2 sin x + 3}{{sin}^{2} x + sin x + 1}

f (x) = \frac{2 {sin}^{2} x + 2 sin x + 3}{{sin}^{2} x + sin x + 1}

f (x)

f (x) = \frac{2 s i n^{2} x - 1}{c o s x} + \frac{c o s x (2 s i n x + 1)}{1 + s i n x}

\int e^{x} (f (x) + f^{'} (x)) d x

f (x) = \frac{2 {sin}^{2} x - 1}{cos x} + \frac{cos x (2 sin x + 1)}{(1 + sin x)}

\int e^{x} (f (x) + f^{'} (x)) d x

c

Join BYJU'S Learning Program