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Byju's Answer
Standard XII
Mathematics
Fractional Part Function
f : R → R is ...
Question
f
:
R
→
R
is a function defined by
f
(
x
)
=
3
{
x
}
−
2
|
x
|
.
Then the value of
f
(
−
0.7
)
−
f
(
−
2
)
is
(Here,
{
.
}
denotes the fractional part function)
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Solution
f
(
x
)
=
3
{
x
}
−
2
|
x
|
⇒
f
(
−
0.7
)
=
3
(
0.3
)
−
2
(
0.7
)
=
−
0.5
⇒
f
(
−
2
)
=
3
(
0
)
−
2
(
2
)
=
−
4
⇒
f
(
−
0.7
)
−
f
(
−
2
)
=
−
0.5
+
4
=
3.5
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Similar questions
Q.
f
:
R
→
R
is a function defined by
f
(
x
)
=
3
{
x
}
−
2
|
x
|
.
Then the value of
f
(
−
0.7
)
−
f
(
−
2
)
is
(Here,
{
.
}
denotes the fractional part function)
Q.
If
f
:
R
→
R
is a function defined by
f
(
x
)
=
[
x
]
cos
(
2
x
−
1
2
π
)
, where
[
x
]
denotes the greatest integer function, then
f
is:
Q.
If
f
:
R
→
R
and
g
:
R
→
R
are functions defined by
f
(
x
)
=
3
x
−
1
;
g
(
x
)
=
√
x
+
6
, then the value of
(
g
∘
f
−
1
)
(
2009
)
is
Q.
If
f
(
x
)
=
x
+
7
and
g
(
x
)
=
x
−
7
,
x
∈
R
, find
(
f
o
g
)
(
7
)
. function
f
:
R
→
R
defined by
f
(
x
)
=
3
x
+
5
2
is an invertible function, find
f
−
1
Q.
Show that the function
f
:
R
→
R
defined by
f
(
x
)
=
3
x
−
1
2
,
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is one-one and onto functions. Also, find the inverse of the function f.
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Standard XII Mathematics
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