Question

$f:R\to R$ is a function defined by $f\left(x\right)=2x+\frac{1}{2}x+\frac{1}{2}$ then $f(-\frac{2}{5})=$

• A. $2$
• B. $-\frac{1}{2}$
• C. $-2$
• D. $\frac{1}{2}$

Answer 1

The correct option is B $-\frac{1}{2}$

$f\left(x\right)=2x+\frac{x}{2}+\frac{1}{2}$
$f(-\frac{2}{5})=2\times -\frac{2}{5}+(-\frac{1}{5})+\frac{1}{2}$
$=-\frac{4}{5}-\frac{1}{5}+\frac{1}{2}$
$=-1+\frac{1}{2}$
$=-\frac{1}{2}$