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Question

f :RR such that f(x+f(x))=4f(x) and f(1)=4. What is the value of f(5)?

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Solution

Given, f(1)=4
We have f(x+f(x))=4(fx)
Put x=1
Therefore, f(1+f(1))=4f(1)
f(1+4)=4(4)
f(5)=16

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