Question 58 (f)
Subtract:
−2a2−2b2 from −a2−b2+2ab.
We have, (−a2−b2+2ab)−(−2a2−2b2)= −a2−b2+2ab+2a2+2b2 On combining the like terms, = −a2+2a2−b2+2b2+2ab= a2+b2+2ab
Question 58 (b)
−a2−ab from b2+ab
Question 3 (vii)
5a2−7ab+5b2 from 3ab−2a2−2b2