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Byju's Answer
Standard XII
Mathematics
Definition of Function
fx=1, if x ...
Question
f
(
x
)
=
1
, if
x
is rational and
f
(
x
)
=
0
, if
x
is irrational
then
(
f
o
f
)
(
√
5
)
=
A
0
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B
1
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C
√
5
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D
1
√
5
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Solution
The correct option is
B
1
Given,
f
(
x
)
=
{
1
; if x is rational
0
; if x is irrational
Consider
x
=
√
5
,
(f o f)
(
√
5
)
=
f
(
f
(
√
5
)
)
=
f
(
0
)
..........
[
∵
√
5
is irrational
]
=
1
..........
[
∵
0
is rational
]
∴
(f o f)
(
√
5
)
=
1
Hence, option B is correct.
Suggest Corrections
0
Similar questions
Q.
If
x
is rational,
f
(
x
)
=
1
else
f
(
x
)
=
0
. Then
f
o
f
(
√
5
)
=
Q.
If
(
x
)
=
1
3
(
f
(
x
+
1
)
+
5
f
(
x
+
2
)
)
a
n
d
f
(
x
)
>
0
f
o
r
a
l
l
x
ϵ
R
,
t
h
e
n
l
i
m
x
→
∞
f
(
x
)
i
s
Q.
Which of the following statements are CORRECT ?
I. If
f
is differentiable in
(
−
∞
,
∞
)
and
lim
x
→
−
∞
f
(
x
)
=
−
∞
and
lim
x
→
∞
f
(
x
)
=
1
,
then the graph of
y
=
f
(
x
)
must cross x-axis.
II.
tan
(
sin
−
1
(
−
4
5
)
−
cos
−
1
(
−
5
13
)
)
is equal to
16
63
.
III. Suppose that
f
(
x
)
is a rational function of
x
and that
f
(
0
)
<
0
and
f
(
2
)
>
0
then there must exist a value of
x
between 0 and 2 where
f
(
x
)
=
0
Q.
If
f
(
x
)
=
1
3
{
f
(
x
+
1
)
+
5
f
(
x
+
2
)
}
and
f
(
x
)
>
0
for all
x
∈
R,
then
lim
x
→
∞
f
(
x
)
is?
Q.
In each of the following, find the value of the constant k so that the given function is continuous at the indicated point;
(i)
f
x
=
1
-
cos
2
k
x
x
2
,
if
x
≠
0
8
,
if
x
=
0
at x = 0
(ii)
f
x
=
(
x
-
1
)
tan
π
x
2
,
if
x
≠
1
k
,
if
x
=
1
at x = 1
(iii)
f
x
=
k
(
x
2
-
2
x
)
,
if
x
<
0
cos
x
,
if
x
≥
0
at x = 0
(iv)
f
x
=
k
x
+
1
,
if
x
≤
π
cos
x
,
if
x
>
π
at x = π
(v)
f
x
=
k
x
+
1
,
if
x
≤
5
3
x
-
5
,
if
x
>
5
at x = 5
(vi)
f
x
=
x
2
-
25
x
-
5
,
x
≠
5
k
,
x
=
5
at x = 5
(vii)
f
x
=
k
x
2
,
x
≥
1
4
,
x
<
1
at x = 1
(viii)
f
x
=
k
(
x
2
+
2
)
,
if
x
≤
0
3
x
+
1
,
if
x
>
0
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