f(x+1)=x-1 find f(x)

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f (x) = \{\begin{cases} \frac{x^{2} - 1}{x - 1}; for & x \neq 1 \\ 2; for & x = 1 \end{cases}

If the function f : R \to R

f (x) = {\begin{matrix} \sqrt{x - 1} if x \geq 1 2 if x < 1 \end{matrix}

f (0)

If f: R $\to$ R is defined by f(x) $= \frac{x}{x^{2} + 1}$ find f(f(2))

f : R \to R

f (x) = \frac{x}{x^{2} + 1}

f (f (2))

f (x) = x - \frac{1}{x}

f (\frac{1}{x}) =

f (x)

f (- x)

- f (x)

\frac{1}{f (x)}

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