f(x) = 2+3cosx

Find the range

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Solution

f(x) = 2+3cosx

We know -1 ≤ cosx ≤ 1

Multiplying by 3,

-3 ≤ 3cosx ≤ 3

Adding 2,

-3+2 ≤ 2 + 3cosx ≤ 3 +2

-1 ≤ 2 + 3cosx ≤ 5

So, range of f(x) is [ -1, 5] Ans.

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