Fx-2x-1- gx-x2-1 f- gx-

The correct option is C 2 x ^ 2 1 Given, f(x)=2x+1, g(x)= x^2 1 We know (f #8728;g)(x)=f(g(x)) #160;Therefore, #160; f(g(x))=f(x^2 1) ...

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Logarithmic Differentiation

fx=2x+1; gx...

Question

$f (x) = 2 x + 1;$ $g (x) = x^{2} - 1$
$(f \circ g) (x) =$

x^{2} + 2 x

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2 x^{3} + x^{2} - 2 x - 1

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2 x^{2} - 1

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4 x^{2} + 4 x

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2 (x^{2} + x + 1)

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Find f o g when f (x) = 2 x + 1

g (x) = x^{2} - 2

I = \int \frac{x^{3}}{\sqrt{x^{2} + 2 x + 5}} d x = \frac{1}{6} f (x) - \frac{A}{120} g (x) + C

f (x) = (2 x^{2} - 5 x - 36) \sqrt{x^{2} + 2 x + 5}, g (x) = log (x + 1 + \sqrt{x^{2} + 2 x + 5})

f (x) = 4 x^{4} + 2 x^{3} + 2 x^{2} + x - 1

g (x) = x^{2} + 2 x - 3

\int \frac{(x - 1) d x}{x^{2} \sqrt{2 x^{2} - 2 x + 1}} = \frac{\sqrt{f (x)}}{g (x)} + C

f (x)

g (x)

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