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Question
f(x)=3+11+71/(1−x) limx→1f(x)=?
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Solution
f(x)=3+11+711−x
f(x)=3+1−x1−x+71
∴f(x)=3+1−x8−x
limx→1f(x)
=limx→1(3+1−x8−x)
=3+1−18−1
=3
f(x)=3+11+711−x
f(x)=3+1−x1−x+71
∴f(x)=3+1−x8−x
limx→1f(x)
=limx→1(3+1−x8−x)
=3+1−18−1
=3
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