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Question

f(x)=4+5x2+6x4 has

A
only one minimum
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B
neither maximum nor minimum
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C
only one maximum
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D
two local minimum
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Solution

The correct option is A only one minimum
f(x)=4+5x2+6x4
f(x)=10x+24x3=2x(5+12x2)
From f(x)=0x=0


Since, sign of f(x) changes from negative to positive as x crosses 0 from left to right, therefore x=0 is a point of local minima.

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