Fx-5 xf-x-A- 5 x x log 5 x secx x tan xB- 1- x tan x 5 x-log 5C- 5 x x log 5D- 1- x 5 x-log 5

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Differentiation of a Determinant

fx=5 xf'x=A. ...

Question

f(x) = 5^{sec x}
f'(x) =

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Solution

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f (x) = \sqrt{x - 2} + \frac{1}{log (5 - x)}

{({log}_{5} x)}^{2} + {log}_{5} x + 1 = \frac{1}{{log}_{5} x - 1}

f (x)

\frac{s i n 3 x + A s i n 2 x + B s i n x}{x^{5}} (x \neq 0)

x = 0

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