$f (x) = a x^{7} + b x^{3} + c x - 5$ where a,b,c are constants. If $f (- 7) = 7$ then $f (7)$ equals to

-17

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Solution

The correct option is A
-17

$f (x) + f (- x) = a x^{7} + b x^{3} + c x - 5 + a (- x)^{7} + b (- x)^{3} + c (- x) - 5$

= $- 5 - 5$

$f (x) + f (- x) = - 10$

$f (x) + 7 = - 10$

$f (x) = - 17$

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f(x) = ax7 + bx3 + cx − 5 where a,b,c are constants. If f(−7) = 7 then f(7) equals to

The correct option is A -17 f(x) + f(−x) = ax7 + bx3 + cx − 5 + a(−x)7 + b(−x)3 + c(−x) − 5 = − 5 − 5 f(x) + f(−x) = −10 f(x) + 7 = −10 f(x) = −17

$f (x) = a x^{7} + b x^{3} + c x - 5$ where a,b,c are constants. If $f (- 7) = 7$ then $f (7)$ equals to

The correct option is A
-17

$f (x) + f (- x) = a x^{7} + b x^{3} + c x - 5 + a (- x)^{7} + b (- x)^{3} + c (- x) - 5$

= $- 5 - 5$

$f (x) + f (- x) = - 10$

$f (x) + 7 = - 10$

$f (x) = - 17$