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Byju's Answer

Standard X

Mathematics

Composition of Function

f x = ax 7+ b...

Question

$f (x) = a x^{7} + b x^{3} + c x - 5$ where a,b,c are constants. If $f (- 7) = 7$ then $f (7)$ equals to

-17

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Solution

The correct option is A
-17

$f (x) + f (- x) = a x^{7} + b x^{3} + c x - 5 + a (- x)^{7} + b (- x)^{3} + c (- x) - 5$

= $- 5 - 5$

$f (x) + f (- x) = - 10$

$f (x) + 7 = - 10$

$f (x) = - 17$

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Similar questions

Q. Let

f (x) = a x^{7} + b x^{3} + c x - 5

, where

a, b

and

c

are constant. If

f (- 7) = 7

, then

f (7)

equals

?

Q. If

f (x) = a x^{7} + b x^{3} + c x - 5 a, b, c

are real constants and

f (- 7) = 7

then the range of

f (7) + 17 cos x

Q. If coefficients of 2, 3 and 4 terms in the binomial expansion of

(1 + x)^{n}

are in A.P, then

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is equal to

Let $\to a = i + 2 j + 3 k$ if $\to b$ is a vector such that $\to a, \to b = | \to b |$ and $| \to a - \to b | = \sqrt{7}$ , then $| \to b | =$ ____________

Q. On subtracting − 7 from − 14, we get

(a) − 12 (b) − 7 (c) −14 (d) 21

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f(x) = ax7 + bx3 + cx − 5 where a,b,c are constants. If f(−7) = 7 then f(7) equals to

The correct option is A -17 f(x) + f(−x) = ax7 + bx3 + cx − 5 + a(−x)7 + b(−x)3 + c(−x) − 5 = − 5 − 5 f(x) + f(−x) = −10 f(x) + 7 = −10 f(x) = −17

$f (x) = a x^{7} + b x^{3} + c x - 5$ where a,b,c are constants. If $f (- 7) = 7$ then $f (7)$ equals to

The correct option is A
-17

$f (x) + f (- x) = a x^{7} + b x^{3} + c x - 5 + a (- x)^{7} + b (- x)^{3} + c (- x) - 5$

= $- 5 - 5$

$f (x) + f (- x) = - 10$

$f (x) + 7 = - 10$

$f (x) = - 17$