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Question

f(x)=∣ ∣cosxx12sinxx22xtanxx1∣ ∣. The value of limx0f(x)x is equal to

A
1
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B
1
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C
0
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D
None of these
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Solution

The correct option is B 0
f(x)=∣ ∣cosxx12sinxx22xtanxx1∣ ∣
Taking x common from C2
limx0f(x)x=limx0∣ ∣cosx112sinxx2xtanx11∣ ∣=∣ ∣111000011∣ ∣=0
Hence, option C is correct.

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