Fx-x32x-1tanx find f-x-

Given f(x)= x^3sec(2x+1)tanx f'(x) = tanx[(3x^2sec(2x+1)+x^3.2sec2x+1)tan(2x+1)] x^2sec(2x+1)sec^2xtan^2x ...

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Antiderivative

fx=x32x+1tanx...

Question

$f (x) = \frac{x^{3} sec (2 x + 1)}{tan x}$ find $f^{'} (x)$ .

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Solution

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