F x -cos- x - x -0 increases in the intervalA- 1-2 k-2- 1-2 k-1B- 1-2 k-1- 1-2 k-3C- None of these D- 1-2 k-1- 1-2 k

The correct option is D f(x) = cos (π/x) Thus f(x) = cos (π/x) increases in 1/3→1/2 generalizing it (1/2k+1, 1/2k) ...

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f x =cosπ/ x ...

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$f (x) = c o s (\frac{π}{x}), x \neq 0$ increases in the interval

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None of these

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f (x) = c o s (\frac{π}{x}), x \neq 0

f (x) = cos (\frac{π}{x}), x \neq 0

k

f (x) = \frac{a_{2 k} x^{2 k} + a_{2 k - 1} x^{2 k - 1} + . . . . + a_{1} x + a_{0}}{b_{2 k} x^{2 k} + b_{2 k - 1} x^{2 k - 1} + . . . . + b_{1} x + b_{0}}

k

a_{i}, b_{i} \in R

a_{2 k} \neq 0, b_{2 k} \neq 0

b_{2 k} x^{2 k} + b_{2 k - 1} x^{2 k - 1} + . . . . . + b_{1} x + b_{0} = 0

A discrete random variable x has following probability distribution

$x : 11234567 P (x) : k 2 k 2 k 3 k k^{2} 2 k^{2} 7 k^{2} + k$

Then k=

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