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Question

f(x)=2x25x+7(x1)(x2)(x3) is continuous or not?

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Solution

2x25x+7=0
x=b±b24ac2a
x=5±254(2)(7)4
x=5±314
Hence 2x25x+7=0 does not have roots as 1,2,3.
Hence f(x) is continuous for all x.

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