Fx - k cos x- -2x if x-2 3 if x-2is continuous at x- -2 Find k-

f(π/2)=RHL at x=(π/2) =lim_h→0f((π/2)+4) =lim_h→0(K(cos(π/2)+h)/π 2((π/2)+h)) =lim_h→0(K( sinh)/ 2h)=(K/2) as #10;f(π/2)=RHL 3=(K/2) ...

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Continuity in an Interval

fx = k cos ...

Question

$f (x) =$ $\frac{k cos x}{π - 2 x}$ if $x \neq \frac{π}{2}$

$3$ if $x = \frac{π}{2}$

is continuous at $x = \frac{π}{2}$ Find $k$ .

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Similar questions

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} \frac{k cos x}{π - 2 x}, & x \neq \frac{π}{2} 3 & a t x = \frac{π}{2} \end{matrix}

x = \frac{π}{2}

k =

k

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} \frac{k cos x}{π - 2 x}, i f x \neq \frac{π}{2} 3, i f x = \frac{π}{2} \end{matrix}

x = \frac{π}{2}

k

x = \frac{π}{2}

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} \frac{k cos x}{π - 2 x}, if x \neq \frac{π}{2} 3, if x = \frac{π}{2} \end{matrix}

f (x) = \{\begin{cases} \frac{k \cos x}{π - 2 x}, & x \neq π / 2 \\ 3, & x = π / 2 \end{cases}

K

f (x)

x = \frac{π}{2}

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} \frac{K . cos x}{π - 2 x}, i f x \neq \frac{π}{2} 3 i f x = \frac{π}{2} \end{matrix}

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