f(x)=27x−9x−3x+1√2−√1+cosx is continuous at x = 0 and f(0)= k√2(log 3)2 then k =
2
4
8
1
limx→10(9x−1)(3x−1)(1−cosx)(√2+√1+cosx)
= 4(log3)(log3).2√2
= 8√(log3)2
f(x)=1−cos(1−cosx)x4 is continuous at x=0, then f(0)=