F x - x -log e x - x -1- is decreasing in intervalA- None of theseB- 1- e C- e - -D- 0- e

The correct option is D (0, e) f'(x) = log_e x . 1 x . 1/x/(log_e x)^2 =(log_e x 1)/(log_e x)^2 0 It is decreasing at (0, e) – 1 ...

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Condition for Monotonically Decreasing Function

f x = x /log ...

Question

$f (x) = \frac{x}{l o g_{e} x}, x \neq 1$ , is decreasing in interval

(0, e)

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(1, e)

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(e, ∞)

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None of these

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