f(x)={3x+5if x≥2x2,if x<2
Discuss the continuity of f(x) at x=2.
We have, f(x)={3x+5if x≥2x2,if x<2
At x=2, LHL=limx→2−(x)2
=limh→0(2−h)2=limh→0(4+h2−4h)=4
and RHL=limx→2′(3x+5)=limh→0[3(2+h)+5]=11
Since, LHL ≠ RHL at x=2
So, f(x)is discontinuous at x=2,