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Question

f(x)={x2 for 0x1x for 1x2 then20f(x)x dx=

A
(13)(42+1)
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B
(13)(421)
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C
(13)(221)
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D
(12)(321)
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Solution

The correct option is B (13)(421)
20f(x) dx=10f(x)dx+21f(x)dx
=13+23(221)=(13)(421)

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