If f(x)=⎧⎪⎨⎪⎩x3,x<03x−2,0≤x≤2x2+1,x>2 Then find the value(s) of x for which f(x)=2.
If f:[−2,2]→R is defined by f(x)={−1, for −2≤x≤0 thenx−1, for 0≤x≤2}
Let f(x)={1+x,0≤x≤23−x,2<x≤3 then f{f(x)}=