f(x) = ln(x) is neither increasing nor decreasing at x = 1.
f(x) = ln(x) f’(x) = 1/x So, f’(1) = 1 which is positive, therefore we can say that it is increasing at x =1.
Prove that the function f given by f(x)=x2−x+1 is neither increasing nor decreasing strictly on (-1, 1).