Fx-sin-8 -e2-1e2 is a constant polynomial-

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fx=sinπ8 +e2-...

Question

$f (x) = sin (\frac{π}{8}) + e^{2} - \frac{1}{e^{2}}$ is a constant polynomial.

True

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False

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f^{'} (x) = f (x) + \int_{0}^{2} f (x) d x, f (0) = \frac{4 - e^{2}}{3}

f (x) = \frac{2}{e^{x} + 1}

[0, 2]

y = y (x)

\frac{d y}{d x} + 2 y = f (x),

f (x) = {\begin{matrix} 1, x \in [0, 1] 0, otherwise \end{matrix}

y (0) = 0

y (\frac{3}{2})

f (x)

= \frac{x}{e^{2} - 1} + \frac{x}{2} + 1

f (x)

lim x \to 0 {(1 + \frac{f (x)}{x^{3}})}^{1 / x} = e^{2}

x = 1

x = 0

2

5 f (3)

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