f(x) = sinx is decreasing about x=π.
True
As we saw, a function is decreasing at a point x = a, if it is decreasing in the neighborhood. So, we will find the value of the function at x = a-h, a and a+h. If we get a relation
f(a-h) ≥ f(a) ≥ f(a+h), then we say that the function is decreasing at x = a. This could be lengthy.
Instead, if we have f’(a) ≤ 0, we can say that the function is decreasing about x =a.
So, we will find f’( π ) to check if the function is decreasing about x = π
f’(x) = cos(x)
f’( π ) = cos ( π ) = -1
Which is negative. So we can clearly say that the function is decreasing about x = π.