$f (x) = \sqrt{x - 3}$ , which inequality can be used to find the domain of $f (x)$ ?

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Solution

$x \geq 3$
The term under the square root must be positive or null:
$x - 3 \geq 0$
That's
$x \geq 3$
then the domain is $[3, \infty)$ .

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f(x)=√x−3, which inequality can be used to find the domain of f(x)?

x≥3The term under the square root must be positive or null:x−3≥0That's x≥3then the domain is [3,∞).

$f (x) = \sqrt{x - 3}$ , which inequality can be used to find the domain of $f (x)$ ?

$x \geq 3$
The term under the square root must be positive or null:
$x - 3 \geq 0$
That's
$x \geq 3$
then the domain is $[3, \infty)$ .