CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

f(x)=tanxtan2x+tan3x,xnπ+π2

A
Is monotonically increasing
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Is monotonically decreasing
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
has a point of maxima
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
has a point of minimum
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Is monotonically increasing
The given equation is:

f(x)=tanxtan2x+tan3x

Differentiating once to find the slope of the function.

f(x)=sec2x2tanxsec2x+3tan2xsec2x

f(x)=sec2x(12tanx+3tan2x)

sec2x>0. This is always true as it a square functiion.

(12tanx+3tan2x)>0

The quadratic roots of teh above equation gives the following result. D=b24ac=412. Tt has complex roots and no real roots. Thus the function is always greater than 0.

Thus f(x)>0

Hence the function is increasing monotonically. ....Answer


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon