F x - x -1 and g x - x 2-2- Find gof at x -2 -A- none of theseB- 0-2C- -0-1-D- -2-0-

The correct option is D [ 2, 0]gof (x) = g(f(x)) = g(x+1) = (x+1)^2 2 = x^2+2x 1 At x = 2 gof = 1 ...

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Functions

f x = x +1 an...

Question

f(x) = x+1 and g(x) = $x^{2} - 2$ . Find (gof) at x = 2?

(0,-2)

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[0,-1]

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[-2, 0]

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none of these

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Solution

The correct option is C [-2, 0]
gof (x) = g(f(x)) = g(x+1) = $(x + 1)^{2} - 2 = x^{2} + 2 x - 1$

At x = 2
gof = -1

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f(x) = x+1 and g(x) = x2−2. Find (gof) at x = 2?

The correct option is C [-2, 0]gof (x) = g(f(x)) = g(x+1) = (x+1)2−2=x2+2x−1 At x = 2 gof = -1

f(x) = x+1 and g(x) = $x^{2} - 2$ . Find (gof) at x = 2?

The correct option is C [-2, 0]
gof (x) = g(f(x)) = g(x+1) = $(x + 1)^{2} - 2 = x^{2} + 2 x - 1$

At x = 2
gof = -1