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B
|x|>1
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C
|x|<2
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D
|x|>2
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Solution
The correct option is A|x|>1 f(x)=x+1x f′(x)=1−1x2 Now f′(x)>0 Gives 1>1x2 Or x2>1 Or |x|>1 ...for f(x) to be an increasing function, Or xϵ(−∞,−1)∪(1,∞)