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Roots of Quadratic Equation

fx=x2+4x-6 f...

Question

$f (x) = x^{2} + 4 x - 6$
$f (x)$ can be written in the form $(x + m)^{2} + n$
Find the value of $m$ and the value of $n$ .

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Solution

$x^{2} + 4 x - 6 = 0$ is Given
we have to write it as
$(x + m)^{2} + n$
so $x^{2} + 4 x - 6$ can be
written as
$x^{2} + 4 x + 4 - 10$
$(x + 2)^{2} - 10$
$∴$ value of m = 2
value of n = -10

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