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B
neither maximum nor minimum
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C
a maximum only
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D
a maximum and a minimum
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Solution
The correct option is B neither maximum nor minimum f(x)=x3−3x2+6x+7 ⇒f′(x)=3x2−6x+6 D=62−4(3)(6)=−36<0
So,f′(x) will be always positive ⇒f(x) will be an increasing function.
Hence, f(x) has neither maximum nor minimum.