atx=0f(0)=0LHL=limh→0f(0−h)=limh→0−h=0RHL=limh→0f(0+h)=limh→0h=0∴continuousatx=0atx=1f(1)=1LHL=limh→0f(1−h)=limh→0(1−h)=1RHL=limh→0f(1+h)=5clearlyf(1)=LHL≠RHLatx=2f(2)=5LHL=limh→0f(2−h)=5RHL=limh→0f(2+h)=5∴continuousatx=2
Is the function f defined by
continuous at x = 0? At x = 1? At x = 2?