$f (x) = | x |$ it is discontinous at.

x = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x = 0$
$f (x) = | x | = {\begin{matrix} x x \geq 0 - x x < 0 \end{matrix}}$
At $x = 0$
$lim x \to 0 f (x)$ doesnot exist
So it is discontinous at $x = 0$

Suggest Corrections

Similar questions

| x - 2 | - 2 | x - 4 | i s

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} [x], & - 2 \leq x \leq - \frac{1}{2} 2 x^{2} - 1, & - \frac{1}{2} < x \leq 2 \end{matrix};

[.]

f (x - 1)

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} x - 1, & x < 0 \frac{1}{4}, & x = 0 x^{2}, & x > 0 \end{matrix}

f (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} x - 1 & x < 0 \frac{1}{4}, & x = 0 x^{2}, & x > 0 \end{matrix}

Join BYJU'S Learning Program