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B
x=1e
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C
x=1
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D
x=√e
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Solution
The correct option is Bx=1e f(x)=xx ⇒logf(x)=xlogx Differentiating wrt x, we get f′(x)f(x)=logx+1 ⇒f′(x)=xx(1+logx) Put f′(x)=0, we get x=1e ∴f(x) has stationary point at x=1e.