f(x,y)=x2+y2+2ax+2by+c=0 represents a circle. If f(x,0)=0 has equal roots, each being 2 and f(0,y)=0 has 2 and 3 as it's roots, then centre of circle is
A
(2,52)
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B
Data are not sufficient
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C
(−2,−52)
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D
Data are inconsistent
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Solution
The correct option is D Data are inconsistent x2+2ax+c=(x−2)2 ⇒−2a=4,c=4 ⇒a=−2,c=4 y2+2by+c=(y−2)(y−3) ⇒−2b=5,c=6 ⇒b=−52,c=6 clearly the data are not consistent.