Factor by grouping
$12 x^{2} - 16 x + 15 x - 20$

(4 x - 5) (3 x + 4)

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(12 x - 5) (x + 4)

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(12 x + 5) (x - 4)

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(4 x + 5) (3 x - 4)

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Solution

The correct option is C $(4 x + 5) (3 x - 4)$
$12 x^{2} - 16 x + 15 x - 20$
on factoring by groups
= $4 x (3 x - 4) + 5 (3 x - 4)$
= $(4 x + 5) (3 x - 4)$

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