Factor completely: $12 x^{2} + 14 x + 4$

2 (3 x + 2) (2 x + 1)

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2 (3 x + 1) (2 x + 1)

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2 (3 x + 2) (2 x + 3)

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2 (2 x + 3) (2 x + 1)

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Solution

The correct option is C $2 (3 x + 2) (2 x + 1)$
We need to factorize ${12 x}^{2} + 14 x + 4$ as
$= 2 (6 x^{2} + 7 x + 2)$
$= 2 (6 x^{2} + 3 x + 4 x + 2)$
$= 2 (3 x (2 x + 1) + 2 (2 x + 1))$
$= 2 (2 x + 1) (3 x + 2)$

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