Factor of $2 {(a + b)}^{2} - 9 (a + b) - 5$ are

a + b + 5, 2 a + 2 b - 1

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a + b - 5, 2 a + 2 b + 1

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a - b + 5, 2 a - 2 b + 5

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None of this

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Solution

The correct option is A $a + b - 5, 2 a + 2 b + 1$
Take $(a + b) = x$
$2 x^{2} - 9 x - 5$
$2 x^{2} - 10 x + x - 5$
$(2 x + 1) (x - 5)$ now put $x = a + b$
so factors are $(2 a + 2 b + 1) (a + b - 5)$

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