Factor the expression using the GCF.
14p-28
We have given expression is (14p-28)firstly we will find the factors of (14p),(28)14p=7×2×p28=7×2×2
We can see that G.C.F of (14p),(28)is 7×2=14Now we will use the GCF to factor the expression
14p-28=14(p)-14(2){Rewritetheexpression}=14(p-2){Distributionproperty}
Final Answer: 14(p-2)
Using the FActor theroem, show that: (i) (x-2) is a factor fo x3−2x2−9x+18 Hence factories the expression (ii) (x+5) is a factor of2x3+5x2−28x−15 Hence factorise fthe expression 2x3+5x2−28x−18 completely. (iii) (3x+2) is a factor fo 3x3+2x2−3x−2. Hence factorise the expression 3x3+2x2−3x−2 completely
Find the greatest common factors (GCF / HCF) of the following polynomials :
2x3y2,10x2y3,14xy
36a2b2c4,54a5c2,90a4b2c2