Question

Factor the quadratic expression $7k^2+9k$ completely.

Answer 1

Factor the quadratic polynomial $\mathbf{7}{\mathit{k}}^{\mathbf{2}}\mathbf{+}\mathbf{9}\mathit{k}$:

Observe that the factor $k$ is common in both terms of the given expression $7k^2+9k$.

Take it out from the expression, $7k^2+9k=k\left(7k+9\right)$.

The two factors $k$ and $\left(7k+9\right)$ are not further factorizable.

Therefore, $7k^2+9k$ is completely factorized to $\mathit{k}\mathbf{(}\mathbf{7}\mathit{k}\mathbf{+}\mathbf{9}\mathbf{)}$.