Factor the trinomial: $3 x^{2} - 4 x - 4$

(3 x + 2) (x - 2)

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(3 x - 2) (x - 2)

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(3 x + 2)^{2}

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(3 x + 2) (x + 2)

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Solution

The correct option is A $(3 x + 2) (x - 2)$
$3 x^{2} - 4 x - 4$
$= 3 x^{2} - 6 x + 2 x - 4$ (Rewrite $- 4 x$ as $- 6 x + 2 x$ to make grouping and factoring easier.)
$= 3 x (x - 2) + 2 (x - 2)$
$= (3 x + 2) (x - 2)$
Therefore $3 x^{2} - 4 x - 4 = (3 x + 2) (x - 2)$

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