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Question

Factories. (1 ) x3+64y3
(2) 24a3+81b3

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Solution

Using the identity a3+b3=(a+b)(a2ab+b2)

(1)x3+64y3

=x3+(4y)3 where a=x,b=4y

=(x+4y)(x2x×4y+(4y)2)

=(x+4y)(x24xy+16y2)

(2)24a3+81b3

=3((2a)3+(3b)3)

=3((2a)3+(3b)3)

=3(2a+3b)(4a26ab+9b2)

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