Factories
15(5x-4)^2-10(5x-4)

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Solution

15(5x-4)^2-10(5x-4)
=(5x-4){15(5x-4)-10}
=(5x-4)(75x-60-10)
=(5x-4)(75x-70)
=(5x-4)5(15x-14)
=5(5x-4)(15x-14)

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Similar questions

Q. 15(5x-4)^2-10(5x-4)

Q. State whether True or False.

Factorization of

15 (5 x - 4)^{2} - 10 (5 x - 4)

5 (5 x - 4) (15 x - 14)

Factorise :

$(i) 15 (5 x - 4)^{2} - 10 (5 x - 4) (i i) 3 a^{2} x - b x + 3 a^{2} - b (i i i) b (c - d)^{2} + a (d - c) + 3 (c - d) (i v) a x^{2} + b^{2} y - a b^{2} - x^{2} y (v) 1 - 3 x - 3 y - 4 (x + y)^{2}$

Q. Factories :

4 - 2 r - 2 r^{2}

Q. Factories:4-(x+y)²

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Factories 15(5x-4)^2-10(5x-4)

15(5x-4)^2-10(5x-4) =(5x-4){15(5x-4)-10} =(5x-4)(75x-60-10) =(5x-4)(75x-70) =(5x-4)5(15x-14) =5(5x-4)(15x-14)

Factories
15(5x-4)^2-10(5x-4)

15(5x-4)^2-10(5x-4)
=(5x-4){15(5x-4)-10}
=(5x-4)(75x-60-10)
=(5x-4)(75x-70)
=(5x-4)5(15x-14)
=5(5x-4)(15x-14)