Question

Factories:${2y}^3+y^2-2y-1$

Answer 1

$2y^3+y^2-2y-1$

$y=1$ is one root

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$2y^2+3y+1=0$

$2y^2+2y+y+1=0$

$2y(y+1)+1(y+1)=0$

$y=-\frac{1}{2},-1$

$\therefore (y+1)(y-1)(y+\frac{1}{2})$