wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorisation of 81x3−xy2 gives


A

x(9xy)(9x+y)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

x2(9x+y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

x(9yx)(9x+y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x(9xy)(9x1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

x(9xy)(9x+y)


We need to factorise the given expression.
81x3xy2
=x(81x2y2) (taking x common)
=x[(9x)2(y)2]
(converting in the form a2b2)
=x[(9xy)(9x+y)]=x(9xy)(9x+y)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon